Question

solve the following activities
$1 + cot \: squre \: \beta = what$

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Answer 1

$1 + \cot ^{2} A$

$\cot = \frac{base}{perpendicular}$

$1 + \cot ^{2} A = 1 + \frac{ {b}^{2} }{ {p}^{2} }$

$= \frac{ {b}^{2} + {p}^{2} }{ {p}^{2} } = \frac{ {h}^{2} }{ {p}^{2} }$

$= cosec ^{2} A$