Question

solve the following
add
7÷-18+5÷-12+-9÷-16

Answer 1

Answer:

$\frac{7}{-18}+\frac{5}{-12} +\frac{-9}{-16}\\ =\frac{-7}{18} -\frac{5}{12} +\frac{9}{16}\\ =\frac{(-7)(8)-(5)(12)+(9)(9)}{144}\\=\frac{-56-60+81}{144}\\ =\frac{-116+81}{144}=\frac{-35}{144}$