Question

solve the following and find out the missing word :-

1) Find the reciprocal of : -3/8 × -7/13.

2) Solve : 3/7+(-6/-11)+(-8/21)+5/22.

3) Find the product of additive inverse and multiplicative Inverse of 15.

Please give the whole solution...
please...❤️​

Answer 1

Answer:

1. -3/8 × -7/13 = 21/104

Reciprocal of  -3/8 × -7/13 = -21/104

2. 3/7 + (- 6/11) + (- 8/21) + (5/22)

Taking L.C.M. of the denominators 7, 11, 21 and 22 and then solving it.

L.C.M. of 7, 11, 21 and 22 = 2*3*7*11

= 462

           

= (462/7)*3 - (462/11)*6 - (462/21)*8 + (462/22)*5

= (198/462) - (252/462) - (176/462) + (105/462)

= (303/462) - (428/462)

= (-125/462)

3. we know additive inverse of any number is 0 and multiplicative inverse is 1.

so additive and multiplicative inverse of 15 are 0 and 1

Answer 2

Step-by-step explanation:

(1) 3/8*7/13

   21/104

   104/21 (reciprocal)

(2) 3/7+6/11-8/21+5/22

    66+42-22+21/462

    109/462

(3) (-15)×(1/15)

    (-1)