solve the following attachment
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length of bigger rectangle be x
length of smaller rectangle=y
perimeter of rectangle=2(l+b)
2(x+6)-2(y+6)=10
2{(x+6)-1(y+6)}=10
x+6-y-6=10/2
x-y=5
x=y+5
area of rectangle=l×b
area of big rectangle=(y+5)×6
6y+30
area of small rectangle =y×6
6y+30-6y=30cm²
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