Math, asked by tanubora2005, 6 months ago


Solve the following ax + by = 5 , bx+ay=3 where a & b are constants​

Answers

Answered by dryogeshkodhawade123
4

Answer:

Let,

ax+by=5 be equation 1 and

bx+ay=3 be equation 2.

Multiply a to the eqation 2 and b to equaiton 1. We get,

abx+b2y=5b

abx+a2y=3a

Now subract the equation. The x terms get cancelled.

b2−a2)y=5b−3a

y=5b−3ab2−a2

Similarly multiply a to eqaution 1 and b to equation 2 and subract them.

y terms get cancel out.

a2x−aby=5a

b2a+aby=3b

We are left with,

(a2−b2)x=5a−3b

x=5a−3ba2−b2

Step-by-step explanation:

above is answer please mark me as brainlist if answer satisfied and share emotions by rating ⭐star⭐

last words,

good night,

follow me,

give ratings,

good bye..........

Similar questions