Solve the following ax + by = 5 , bx+ay=3 where a & b are constants
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Answer:
Let,
ax+by=5 be equation 1 and
bx+ay=3 be equation 2.
Multiply a to the eqation 2 and b to equaiton 1. We get,
abx+b2y=5b
abx+a2y=3a
Now subract the equation. The x terms get cancelled.
b2−a2)y=5b−3a
y=5b−3ab2−a2
Similarly multiply a to eqaution 1 and b to equation 2 and subract them.
y terms get cancel out.
a2x−aby=5a
b2a+aby=3b
We are left with,
(a2−b2)x=5a−3b
x=5a−3ba2−b2
Step-by-step explanation:
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