(Solve the following
Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.) please it is very urgent and please follow me i will follw you back
Answers
Step-by-step explanation:
Given :-
Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6.
To find:-
Find the ratio of areas of these triangles.
Solution:-
Base of the first triangle (b1)=9 units
Height of the first triangle (h1)=5 units
Base of the second triangle (b2)=10units
Height of the second triangle (h2)=6 units
Formula:-
If the base 'b' units and height is 'h' units then the area of a triangle is 1/2(bh) sq.units.
Now ,
Area of the first triangle (A1)=(1/2)b1h1 sq.units
=>A1=(1/2)9×5 sq.units
=>A1= 45/2 sq.units...........(1)
Area of the secondtriangle(A2)
=(1/2)b2h2
=>A2=(1/2)10×6 sq.units
=>A2=60/2 sq.units
=>A2=30 sq.units.........(2)
Ratio of their areas =A1:A2
=>A1:A2=45/2:30
=>A1:A2=45:60
=>A1:A2=45/60
=>A1:A2=(3×15)/(4×15)
=>A1:A2=3/4
=>A1:A2=3:4
Answer :-
The ratio of the areas of the two triangles is 3:4
Answer:
3:4 is the answer for your question