Question

Solve the following by elimination method . (1) 2 x+3 y = 8 , 4 x+6 y = 7
(2) 3x+2y= 8 , 2x- 3y = 7​

Answer 1

$\huge\mathfrak\ \red {★AnSweR}$

2x+3y=8....(i)

4x+6y=7..(ii)

Multiply (i) by 4

4x+6y=16...(iii)

LHS of (ii) and (iii) are same but RHS is different

Hence the solution does not exist.

Answer 2

refers to the above attachment...