Question

Solve the following by elimination method.

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Answer 1

Answer:

4x+3y=4

6x+5y=8

3*(4x+3y=4)

it becomes

12x+9y=12. eq1

2*(6x+5y=8)

and this becomes

12x+10y=16. eq2

now subtracting eq2 from eq1 we get

12x+9y=12

-(12x+10y=16)

-y=-4

y=4

4x+3y=4

4x+12=4

4x=-8

x=-2

Answer 2

Step-by-step explanation:

4x+3y=4......eq1

6x+5y=8.......qu2

5x....4x+3y=4

3x....6x+5y=8

20x+15y=20

- 18x+15y=24

____________________

2X+0= - 4

X=-4/2

X= - 2

SUB X=-2 IN EQ1 OR EQ2

NOW

EQ1=4X+3Y=4

4(-2)+3Y=4

- 8+3Y=4

3Y=12

Y=4

(X,Y)=(-2,4)

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