Question

solve the following by factorisation:
1:2x^2+x-6.
2:100x^2-20x+1.
PLZZ solve this questions..
plzzzzzzz​

Answer 1

Answer:

Solution :

Given Quadratic equation

2x² + x - 6 = 0

Splitting the middle term , we get

2x² + 4x -3x - 6 = 0

=> 2x( x + 2 ) - 3( x + 2 ) = 0

=> ( x + 2 )( 2x - 3 ) = 0

Therefore ,

x + 2 = 0 or 2x - 3 = 0

x = -2 or x = 3/2

•••••

Step-by-step explanation:

2. Given quadratic equation:

100x²-20x+1=0

=> (10x)² -2*(10x)+1² = 0

=> (10x-1)² = 0

/* By algebraic identity

a²-2ab+b² = (a-b)² */

=> 10x-1 = 0 or 10x-1 = 0

=> 10x = 1 or 10x = 1

=> x = 1/10 or x = 1/10

[ equal roots ]

Therefore,

1/10, 1/10 are two roots of given Quadratic equation.

•••

Answer 2

Answer:

Step-by-step explanation:

$1) 2x^{2} +x-6 = (x-3)(x+4)$

$2) 100x^{2} - 20x + 1 = (10x-1)(10x-1)\\ = (10x-1)^{2}$