Question

solve the following by factorisation. 1) 7y-3y²-4=0​

Answer 1

Step-by-step explanation:

7y-3y^2-4=0

-3y^2 + 7y - 4=0

-3y^2 + 3y + 4y - 4 = 0

-3y ( y - 1) + 4 (y - 1) = 0

(y - 1) + (-3y + 4) = 0

Either y - 1 = 0

y = 1

Or - 3y + 4 = 0

y = 4/3