Solve the following by factorisation method
q2 +q - 12 = 0
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Answer:
q²+q-12=0
q²+4q-3q-12=0
(q²+4q)-(3q-12)=0
q(q+4)-3(q+4)=0
(q+4)(q-3)=0
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q²+q-12=0
On middle splitting,
q²+4q-3q-12=0
Now by taking common,
q(q+4)- 3(q+4)=0
(q-3) (q+4)=0
Now, On equating equation from 0,
q= 3, -4
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