Question

solve the following by matrix method x+y=1, 3y+3z=5, 3z+3x=4​

Answer 1

Step-by-step explanation:

Using first equation we have

x+y = 1

y = 1-x

using third equation we have

3(z+x) = 4

z+x = 4/3

z = 4/3 - x

replace z and y in second equation to find x :-

3(1-x) + 3(4/3 - x) = 5

3-3x+4-3x = 5

7-6x = 5

7-5 = 6x

6x = 2

x = 2/6 = 1/3

now y = 1-1/3 = (3-1)/3 = 2/3

and z = 4/3 - 1/3 = 3/3 = 1

X = 1/3

Y = 2/3

Z = 1

Hope this helps