Question

Solve the following by reducing to quadratic equation.
x⁴- 26x² +25=0​

Answer 1

Answer:

Reduce the polynomial as q e

Put x^2= a

Hence the given equation is

a^2 --26 a +25 =0

a^2 --25a --a +25 =0

a (a--25) - -- -1( a--25) =0

a-1 =0

a=1.

x^2 =1

x=+1. x= --1

a--25 =0

a=25

x^2=25

x = +5. --5

Answer 2

Step-by-step explanation:

given x⁴-26x²+25=0

putting x²=y.the given equation reduces to form y²-26y+25=0

= y²-25y-y+25=0

= y(y-25)-1(y-25)=0

= (y-25)(y-1)=0

= y-25=0 or y-1=0

= y=25 or y=1

x²=25

x=5

or x²=1