Question

Solve the following by subsitution,elimination and cross multiplication method.
8x+5y=9
3x+2y=4

Answer 1

8x+5y=9.......*2.

3x+2y=4.......*5

16x+10y=18......(1)

15x+10y=20......(2)

equation 2 is substrate from equation 1

then,x= -2

y=5

Answer 2

by substitution method ,

we have :-

8x +5y = 9 ..................................(I)

3x + 2y = 4

then ,

x = 4 - 2y

3

on putting this value in equation 1 we get ,

8 × (4 -2y) + 5y = 9g

3

32 - 16y + 15y = 9

3

32 - y = 9×3

y = 32 -27

y = 5

then ,

x= 4 -2×5 = -6 = -2

3 3

thus, x = -2

y= 5 answer

------------------------------------------------------

by elimination method ,

we have :-

8x + 5y = 9 ..........(I)

3x + 2y = 4 ..........(ii)

on multiplying in equation I by 2 and in equation ii by 5 we get ,

16x + 10y = 18 ........(iii)

and, 15x + 10y = 20 .......(iv)

on subtracting equation iii and iv we get ,

16x + 10y = 18

-15x - 10y = - 20

x = -2

on putting this value in equation ii we get ,

3×(-2) + 2y = 4

=} -6 + 2y = 4

=} y = 6 + 4

2

=} y = 10

2

=} y = 5

thus ,

x = -2

and, y = 5 answer

I hope it will help you bhai itni typing karke vo bhi math me thak gaya hu umid hai ye tumahri madda karegi.....

thanks to give e a chance to solve it.