Solve the following by subsitution,elimination and cross multiplication method.
8x+5y=9
3x+2y=4
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8x+5y=9...... equation 1
3x+5y=4...... equation 2
from 1st equation
x=(9-5y)/8
put the value in 2nd equation
3(9-5y)/8 +2y=4
(27-15y)/8 +2y=4
(27-15y+16y)/8=4
27+y=4×8
y=32-27
y=5
y=5 put the value in 1st equation
8x+5×5=9
8x=9-25
x=-16/8
x=-2
titanx4:
which method is this???
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