Question

solve the following by substituition method 3x-y+7/11+2=10 and 2y+x+11/7=10

Answer 1

solve the pair of linear equation:
3x - y + 7/11 + 2 = 10
2y + x + 11/7 = 10
We can rearrange these equations to
3x - y + 7/11 = 8
x + 2y + 11/7 = 10
get rid of those annoying fractions
multiply the 1st equation by 11
multiply the 2nd equation by 7
33x - 11y + 7 = 88
7x + 14y + 11 = 70
which is
33x - 11y = 81
7x + 14y = 59
These are a pain, lets solve it graphically
-11y = -33x + 81
divide by -11
y = 3x - (81/11)
and
14y = -7x + 59
y = -(1/2)x + (59/14)


my calc calls this x = 3.308, y = 2.56 (checks out in the 1st equation)

hope. it helps