Question

solve the following by substitution method-
s-t=3
s÷3+t÷2=6​

Answer 1

Answer:

by substitution

s - t = 3

s = 3 + t

so

3 + t / 3 + t / 2 = 6

by lcm

6 + 2t + 3t / 6 = 6

6 + 5t = 36

5t = 30

t = 6

s = t + 3 = 9

Answer 2

Answer:

t=6, s=9

Step-by-step explanation:

s-t=3

so, s=3+t

substituting the value of s in the 2nd equation --->

s÷3+t÷2=6

[(3+t)÷3]+(t÷2)=6

taking L.C.M of 3 and 2

[(3+t)2 + (t)3] ÷ 6 = 6

[6+2t + 3t] ÷ 6 = 6

6+5t = 6×6

5t = 36-6

t = 30÷5

t=6

putting this value in equation 1 --->

s-t=3

s-6=3

s=3+6

s=9