Question

Solve the following by substitution method:
x+4y=-4. 3y-5x=-1

Answer 1

The value of x and y are $-\frac{8}{23}$ and $-\frac{21}{23}$.

Step-by-step explanation:

The equations are:

$x+4y=-4...(i)\\3y-5x=-1...(ii)$

Fro equation (i) the value of x is:

$x=-4-4y$

Substitute the value of x in (ii) and solve for y as follows:

$3y-5x=-1\\3y-5(-4-4y)=-1\\3y+20+20y=-1\\23y=-21\\y=-\frac{21}{23}$

Substitute y in $x=-4-4y$ and solve for x as follows:

$x=-4-4y\\=-4-(4\times -\frac{21}{23})\\=-4+\frac{84}{23}\\=-\frac{8}{23}$

Thus, the value of x and y are $-\frac{8}{23}$ and $-\frac{21}{23}$.

Learn more:

https://brainly.in/question/132055

Answer 2

there is no change in this question