solve the following by systematic method 3×+12=28
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3x+12=28
3x+12-12=28-12(subtracting 12 from both sides
3x+0=16
3x/3=16/3... dividing both sides by 3
x=16/3
3x+12-12=28-12(subtracting 12 from both sides
3x+0=16
3x/3=16/3... dividing both sides by 3
x=16/3
shivjit:
thanks
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