Question

Solve the following , by using factor method.
${x}^{2} - 14x + 13 = 0$
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Answer 1

⤿Given Equation :

x² - 14x + 13

⤿Solution :

$\\ \sf{x}^{2} - 14x + 13 \\ \\ \sf \: {x}^{2} - 13x - x + 13 \\ \\ \sf \: x(x - 13) - 1(x - 13) \\ \\ \sf \red{(x - 1)(x - 13)} \\ \\ \sf Roots \: \: of \: \: given \: \: eqⁿ are ↓ \\ \\ \boxed{\pink{\sf x = 10 \: \: or \: \: x = 13}}$

⤹From factor method above eqⁿ can also be written as :

$\\ \\ {\boxed{ \huge \green{ \tt(x - 1)(x - 13)}}}$