Question

SOLVE THE FOLLOWING.

CLASS 8​

Answer 1

Let 3 consecutive multiple of 8

8x,8(x+1),8(x+2)

Sum=8x+8(x+1)+8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1=

3

111

x+1=37

x=36

First multiple =8x=8×36=288

Second =8(x+1)=8×37=296

Third =8(x+2)=8×38=304