Question

SOLVE THE FOLLOWING

CLASS 8​

Answer 1

$\huge{ Answer :-}$

6 :- Let the first multiple of 8 be 8x. Also the third consecutive multiple of 8 will be 8(x+2). => x = 36. If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

5 :- Three consecutive integers add up to 51. The three consecutive integers are 16,17 and 18.

4 :- Let x be common ratio

∴ numbers will be 5x and 3x respectively.

Difference between these numbers ⇒18

5x−3x=18

2x=18

Divide both sides by 2.

2

2x

=

2

18

x=9

∴ First number =5x=5×9=45

Second number =3x=3×9=27

Answer 2

Solution:

Let the present ages of Hari and Harry be 5x years and 7x years respectively.

After 4 years Hari’s age will be (5x + 4) years and Harry’s age will be (7x + 4) years.

As per the conditions, we have

5x+47x+4=34

⇒ 4(5x + 4) = 3(7x + 4) (Cross-multiplication)

⇒ 20x + 16 = 21x + 12 (Solving the bracket)

⇒ 20x – 21x = 12 – 16 (Transposing 21x to LHS and 16 to RHS)

⇒ -x = -4

⇒ x = 4

Hence the present ages of Hari and Harry are 5 × 4 = 20years and 7 × 4 = 28years respectively.