SOLVE THE FOLLOWING
Consider the following three compounds (i) AXn-2n (1)
AX3n, and (iii) AXn+4n, where central atom A is 15th group
element and their maximum covalency is 3n. If total number
of proton in surrounding atom X is n and value of n is one,
then calculate value of "x3+ y2 + z". (Where x, y and z are
total number of lone pair at central atom in compound (1).
(ii) and (iii) respectively.
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Answer:(i) NH 2− (ii) NH 3 (iii) NH 4+ lone pair x = 2 , y = 1, z = 0x 3 +y 2 +z=(2) 3 +(1) 2 +(0)=9
Explanation:
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