Question

solve the following
cosec^2Q.tan^2Q -1=tan^2Q

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Answer 1

Answer:

LHS,

cosec^2Q.tan^2Q-1

=1/sin^2Q.sin^2Q/cos^2Q-1

=1/cos^2Q-1

=sec^2Q-1

=tan^2Q=RHS

Answer 2

Answer:

п/2

Step-by-step explanation:

cosec²Q.tan²Q-1=tan²Q

(1+cot²Q)(sec²Q-1)=tan²Q

(1+cos²Q/sin²Q)(1/cos²Q-1)=tan²Q

(sin²Q+cos²Q)/sin²Q(1-cos²Q)/cos²Q=tan²Q

1/sin²Q.sin²Q/cos²Q=tan²Q

sec²Q=sin²Q/cos²Q

sin²Q=1

Q=п/2

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