solve the following determinant & find the value of x
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3x-8[(3x-8)²-9)]-3[3(3x-8)-9]+3[9-3(3x-8)]=0
3x-8(9x²+64-48-9)-3(9x-24-9)+3(9-9x+24)=0
3x-8(9x²+7)-3(9x-33)+3(33-9x)=0
27x³+21x-72x²-56-27x+99+99-27x=0
27x³-72x²-33x+198-56=0
27x³-72x²-33x+141=0
9x³-24x²-11x+47=0
BY SOLVING FOR X WE GET X VALUE....
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