Solve the following differential equation:
(D ^ 3 - 9D ^ 2 + 27D - 27) * x = 5 * (e ^ 5) ^ (2y) + 1 + 2y + 3y ^ 2
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⭐ Answer⭐
The given equations are
⇒ x + 2y = – 1 … (i)
⇒ 2x – 3y = 12 …(ii)
From equation (i), we get
⇒ x = – 1 – 2y … (iii)
Putting x’s value in Equation (ii), we get
⇒ 2(- 1 – 2y) – 3y = 12
⇒ – 2 – 4y – 3y = 12
⇒ – 7y = 14
⇒ y = 14/- 7
⇒ y = – 2
Putting y’s value in equation (iii), we get
⇒ x = – 1 – 2y
⇒ x = – 1 – 2 × (- 2)
⇒ x = – 1 + 4
⇒ x = 3
Here, x = 3 and y = – 2.
Hence, the solution of the given equation is x = 3, y = – 2
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