Math, asked by guddubhadoriya910, 9 months ago

Solve the following (Each question carries 2 marks)
(10 Marks)
Q. 6 It is given that in a group of 3 students, the probability that the 2 students have the
same birthday is 0.008. What is the probability that the students not having the same
birthday?
0.7 Use Euclid's division algorithm to find H.C.F. of 135 and 225.​

Answers

Answered by rohitnagargoje135
1

Answer:

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Step-by-step explanation:

let

the number of same birthday in student =×

the number of student in one group = 3 x

3

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