Question

Solve the following equati
dy
1. Ž+y=1 (y + 1).
dx​

Answer 1

Answer:

sorry for the late reply I was just wondering if you have any questions please feel free to contact me at any time

Answer 2

Answer:

dydx=(1+x)(1+y)

this is separable!

11+ydydx=1+x

so we integrate both sides

∫ 11+ydydx dx=∫ 1+x dx

or

∫ 11+y dy=∫ 1+x dx

ln(1+y)=x+x22+C

1+y=ex+x22+C

y=Cex+x22−1

Step-by-step explanation: