solve the following equatiom 3(2x+1)=2(x+4)'
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3(2x−1)²+4(2x−1)−4=0
say t=2x−1, then⇒3t²+4t−4=0
⇒3t²+6t−2t−4=0
⇒3t(t+2)−2(t+2)=0
⇒(3t−2)(t+2)=0
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