Math, asked by Ashikaku, 6 months ago

solve the following equation
1. 20p/3=40
2. 2 q+ 6 =12
3. x- 1 =5
4. 3(n -1)=21
5 a\ 5 + 3 =2

Answers

Answered by ananthamananth682
1

Answer:

20p/3=40

20p=120

p=120/20

p=6

2.2q+6=12

2q=12-6

2q=6

q=6/2

q=3

3.x-1=5

x=5+1

x=6

4.3(n-1)=21

3n-3=21

3n=21+3

n=24/3

n=8

5.a/5+3=2

a+15=10

a=10-15

a=-5

Answered by rajputroshni542
0

Answer:

1.

\frac{20}{3}p = 40 \\   \\ \frac{3.20}{3} p = 3.40p

2.

2q + 6 = 12 \\  \\ 2q = 6 \\  \\  \frac{2}{2}q =   \frac{6}{2} \\  \\ q = 3

3.

x - 1 = 5 \\  \\ x - 1 + 1 = 5 + 1 \\  \\ x = 6

4.

3(n - 1) = 21 \\  \\ 3n - 3 = 21 \\  \\ n = 8

5.

\frac{a}{5} + 3 = 2 \\ \\   \frac{a}{5} + 3 - 3 = 3 - 2 \\  \\ a =  - 5

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