Math, asked by shokatjhan678, 11 months ago

Solve the following equation
1) 2x-5=3(x-5)
2) 7x=5x +8
3)4x=x+15
4)2x/3+1=7x/15+3

Answers

Answered by kaurmehakkhalsa
4

Answer:

i) \\ 2x - 5 = 3(x - 5) \\ 2x - 5 = 3x - 15 \\ 2x - 3x = 5 - 15 \\  - x =  - 10 \\ x = 10 \\  ii) \\ 7x = 5x + 8 \\ 7x - 5x = 8 \\ 2x = 8 \\ x =  \frac{8}{2}  = 4 \\ iii) \\ 4x = x  + 15 \\ 4x - x = 15 \\ 3x = 15 \\ x =  \frac{15}{3}  = 5 \\  iv) \\  \frac{2x}{3}  + 1 =  \frac{7x}{15}  + 3 \\  \frac{2x}{3}  -  \frac{7x}{15}  = 3 - 1 \\  \frac{10x - 7x}{15}  = 2 \\  \frac{3x}{15}  = 2 \\  \frac{x}{5}  = 2 \\ x = 2 \times 5 \\ x = 10 \\  \\

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Answered by RohanBabhale
4

\blue{\bold{\underline{\underline{\huge{\boxed{\star{\mathcal{\textit  {Answer: }}}}}}}}} \:

1)2x - 5 = 3x - 15 \\ 15 - 5 = 3x - 2x \\ 10 = x \\ 2)7x = 5x + 8 \\ 7x - 5x = 8 \\ 2x = 8 \\

x = 4 \\ 3)4x = x + 15 \\ 4x - x = 15 \\ 3x = 15 \\ x = 5 \\ 4) \frac{2x}{3} + 1 =  \frac{7x}{15}  + 3 \\  \frac{2x + 3}{3 }  = \frac{7x + 45}{15}  \\  10x + 15 = 7x  +  45 \\ 3x = 30 \\ x = 10

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