Math, asked by sharmisthadas62, 1 month ago

solve the following equation. 1. 3x - x=8​

Answers

Answered by aayushdevre11
0

ANSWER :-

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Given, 3x+

Given, 3x+ x

Given, 3x+ x1

Given, 3x+ x1

Given, 3x+ x1 −8=0

Given, 3x+ x1 −8=0⇒

Given, 3x+ x1 −8=0⇒ x

Given, 3x+ x1 −8=0⇒ x3x

Given, 3x+ x1 −8=0⇒ x3x 2

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2 +bx+c=0,a

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2 +bx+c=0,a

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2 +bx+c=0,a=0

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2 +bx+c=0,a=0Here, a=3

Given, 3x+ x1 −8=0⇒ x3x 2 +1−8x =0⇒3x 2 +1−8x=0Comparing it with the standard form of quadratic equation x 2 +bx+c=0,a=0Here, a=3Thus, it is a quadratic equation

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HOPE IT HELPS YOU ❤️

Answered by ruchagamergirl
1

Answer:

3x-x=8

2x=8

x=4

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