Question

solve the following equation: (1) 4(2x+1)=3(x-1)+7. (2) 3(2p-1)=5-(3p-2).

Answer 1

$(i) \: \: 4(2x + 1) = 3(x - 1) + 7 \\ \\ 8x + 4 = 3x - 3 + 7 \\ \\ 8x + 4 = 3x + 4 \\ \\ 8x - 3x = 4 - 4 \\ \\ 5x = 0 \\ \\ x = 0$

$(ii) \: \: 3(2p - 1) = 5 - (3p - 2) \\ \\ 6p - 1 = 5 - 3p + 2 \\ \\ 6p + 3p = 5 + 2 + 1 \\ \\ 9p = 8 \\ \\ p = \frac{8}{9}$

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Answer 2

Hola Mate!❤

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Question: Solve the following equations.

i) 4(2x+1)=3(x-1)+7

ii) 3(2p-1)=5-(3p-2)

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Answer

i) 4(2x+1) = 3(x-1) + 7

  8x + 4 = 3x - 3 + 7

  8x + 4 = 3x + 4

  8x - 3x = 4 - 4

         5x = 0

           x = 0/5

          x = 0

ii) 3 (2p -  1) = 5 - (3p - 2) (negative sign is mulitiplied to 3p and 2)

     6p - 3 = 5 - 3p + 2

  6p + 3p = 7 + 3

          9p = 10

            p = 10/9

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