Question

Solve the following equation

Answer 1

x=-1021 and y=1406 using substitution method.

Answer 2

Given pair of linear equations,
x/3+y/4=11......................................................1

5x/6-y/3=-7...................................................2
By solving eq 1 and eq2 we get,
(4x+3y)/12=11

4x+3y=132

4x=132-3y

x=(132-3y)/4................................................3
and,
(5x-2y)/6=-7

5x-2y=-42............……………………..............4
Putting eq3 in eq4 we get,
5[(132-3y)/4]-2y=-42

660-15y-8y=-168

23y=828

y=36
Putting value of y in eq3 we get,
x=(132-108)/4

x=24/4

x=6


Hence value of x=6 and y=36.