Question

solve the following equation √13+√16+√4=√(k+2)²+√(k-1)²​

Answer 1

Answer:

For equal roots D = 0

[2(k − 12)]²4.(k − 12).2 = 0

4(k-12)² - 4(k - 12) × 2 = 0

k² - 24k + 144 - 2k + 24 = 0

or k² 26k + 168 = 0

k² - 14k - 12k + 1680

k(k − 14) – 12(k − 14) = 0

(k-12) (k-14) = 0

... k = 12 or 14

.. k = 14 (ask # 12given in question)

Answer 2

Answer:

√13+√16+√4=√(k+2)²+√(k-1)²

√13+4+2=k+2+k-1

√13+6=2k+1

k=√13+6-1

k{√13+5

HOPE IT WILL HELP YOU