Question

solve the following equation 13(y-4)-3(y-9)-5(y+4)=0

Answer 1

Answer:

value of y = 9

Step-by-step explanation:

13(y-4)-3(y-9)-5(y+4)=0

=> 13y - 52 - 3y + 27 - 5y - 20 = 0

=> 13y - 3y - 5y - 52 + 27 - 20 = 0

=> (13-3-5)y - 72 + 27 = 0

=> (13-8)y - 45 = 0

=> 5y - 45 = 0

=> 5y = 45

/* Divide each term by 5 , we get

=> y = 9

Therefore,

Value of y = 9

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Answer 2

Answer:

=> y = 9

Step-by-step explanation:

Given equation -

$13(y-4)-3(y-9)-5(y+4)=0$

We have to simplify the equation,

For that, we have to distribute the terms:

$=> 13(y-4)-3(y-9)-5(y+4)=0$

$=> 13 y-52-3(y-9)-5(y+4)=0$

$=> 13 y-52-3 y+27-5(y+4)=0$

$=> 13 y-52-3 y+27-5 y-20=0$

Now, add the numbers:

$=> 13 y-45-3 y-5 y=0$

Combining the like terms, we get

$=> 5 y-45=0$

Add both sides by $45$ we get,

$=> 5 y-45+45=0+45$

$=> 5y = 45$

Divide both sides by $5$, we get

$=> y = 9$

Hence, the simplified value is 9.