Question

solve the following equation​

Answer 1

Answer:

(I) 5y-7/3y=2

We move all terms to the left:

5y-7/3y-(2)=0

Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R

We multiply all the terms by the denominator

5y*3y-2*3y-7=0

Wy multiply elements

15y^2-6y-7=0

a = 15; b = -6; c = -7;

Δ = b2-4ac

Δ = -62-4·15·(-7)

Δ = 456

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

y1=−b−Δ√2ay2=−b+Δ√2a

The end solution:

Δ−−√=456−−−√=4∗114−−−−−−√=4√∗114−−−√=2114−−−√

y1=−b−Δ√2a=−(−6)−2114√2∗15=6−2114√30

y2=−b+Δ√2a=−(−6)+2114√2∗15=6+2114√30

sorry yrr I know this one only

Answer 2

Answer:

-7

Step-by-step explanation:

5y-7/3y=2

5y-7=2×3y

5y-7=6y

-7=6y-5y

-7=y

PLS MARK AS BRAINLIEST