Question

solve the following equation 2x^2-3x-35=0​

Answer 1

Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(2x2 - 3x) - 35 = 0

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 2x2-3x-35

The first term is, 2x2 its coefficient is 2 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is -35

Step-1 : Multiply the coefficient of the first term by the constant 2 • -35 = -70

Step-2 : Find two factors of -70 whose sum equals the coefficient of the middle term, which is -3 .

-70 + 1 = -69

-35 + 2 = -33

-14 + 5 = -9

-10 + 7 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 7

2x2 - 10x + 7x - 35

Step-4 : Add up the first 2 terms, pulling out like factors :

2x • (x-5)

Add up the last 2 terms, pulling out common factors :

7 • (x-5)

Step-5 : Add up the four terms of step 4 :

(2x+7) • (x-5)

Which is the desired factorization

Equation at the end of step

2

:

(x - 5) • (2x + 7) = 0

STEP

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