Math, asked by shabarozb, 9 months ago

solve the following equation 2x-2(4y-1) =2(3y-1)​

Answers

Answered by srajfaroquee
1

Answer:

2 × -2 (4y - 1) = 2(3y -1)

⇒ 2 × -8y + 2 = 6y - 2

⇒ -16y -6y = -2 -2

⇒ -22y = -4

⇒ y = \frac{2}{11}

Answered by Anonymous
2

Answer :

\implies \sf 2\: \times \:-\:2(4y\:-\:1)\:=\:2(3y\:-\:1) \\

\implies \sf 2 \: \times (\:-\:8y\:+\:2)\:=\:6y\:-\:2 \\

\implies \sf -16y\:+\:4\:=\:6y\:-\:2 \\

\implies \sf -16y\:-\:6y\:=\:2\:-\:4 \\

\implies \sf -22y\:=\:-2 \\

\implies \sf y\:=\:-\: \dfrac{2}{22} \\

\:\:\:\:\:\:\:\:\:\large\bold\bigstar \:\:\:\: {\boxed{\boxed{\tt{\orange{y\:=\:-\: \dfrac{1}{11}}}}}}

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