Solve the following equation 2x+4/x-1 >5
Answers
Answered by
1
We have
x−1
2x+4
≥5⇒
x−1
2x+4
−5≥0
⇒
x−1
2x+4−5(x−1)
≥0⇒
x−1
2x+4−5x+5
≥0
x−1
−3x+9
≥0 [Multiplying both sides by -1]
x−1
3x−9
≤0⇒
x−1
3(x−3)
≤0 [Dividing both sides by 3]
x−1
x−3
≤0⇒1Hence the solution set of the given inequations is (1, 3]
x−1
2x+4
≥5⇒
x−1
2x+4
−5≥0
⇒
x−1
2x+4−5(x−1)
≥0⇒
x−1
2x+4−5x+5
≥0
x−1
−3x+9
≥0 [Multiplying both sides by -1]
x−1
3x−9
≤0⇒
x−1
3(x−3)
≤0 [Dividing both sides by 3]
x−1
x−3
≤0⇒1Hence the solution set of the given inequations is (1, 3]
Answered by
0
Answer:
Answer
We have
x−1
2x+4
≥5⇒
x−1
2x+4
−5≥0
⇒
x−1
2x+4−5(x−1)
≥0⇒
x−1
2x+4−5x+5
≥0
x−1
−3x+9
≥0 [Multiplying both sides by -1]
x−1
3x−9
≤0⇒
x−1
3(x−3)
≤0 [Dividing both sides by 3]
x−1
x−3
≤0⇒1<x≤3⇒x∈(1,3]
Hence the solution set of the given inequations is (1, 3]
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