Question

solve the following equation 3(2x+3)=5(4x-x)​

Answer 1

Step-by-step explanation:

6x + 9 = 20x - 5x

6x + 9 = 15x

9= 15x - 6x

9 = 9x

x = 1

I HOPE IT WILL USE FULL

Answer 2

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$\bold{Explanation:}$

$\sf = > 3\bigg(2x + 3\bigg) = 5\bigg(4x - x\bigg)$

$\sf = > 3\bigg(2x + 3\bigg) = 5\bigg(3x\bigg)$

$\sf= > 6x + 9 = 15x$

Taking variable term together and constant on the other side to find out the value of 'x'

$\sf = > 6x -15x = -9$

$\sf =>-9x = -9$

$\sf=> x = \dfrac{9}{9} = 1$

$\sf\huge x = 1$

Check:-

$\sf= > 3\bigg[2\bigg(1\bigg) + 3\bigg] = 5\bigg[4\bigg(1\bigg)- \bigg(1\bigg)\bigg]$

$\sf= > 3\bigg(2 + 3\bigg) = 5\bigg(4 - 1\bigg)$

$\sf = > 3 \times 5 = 5 \times 3$

$\sf 15 = 15$

LHS=RHS Verified

Extra information=>

Above Equation 3(2x+3)=5(4x-x)=6x+9=15x

Is a monomial term as highest degree in the term is one.