solve the following equation 3/4y+2,y=1/2+4y out
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(
4
3(y−5)
)−4y=3−(
2
(y−3)
)
3(y−5)−16y=12−2(y−3)
3y−15−16y=12−2y+6
3y−16y+2y=12+6+15
−11y=33
∴y=−3
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