Math, asked by prithvipradeep08, 10 days ago

Solve the following equation 3 = 9 ( p−10)

Answers

Answered by sitarasahu42
1

Answer: 331

Step-by-step explanation:

1

Distribute

3=9(−10)

3={\color{#c92786}{9(p-10)}}3=9(p−10)

3=9−90

3={\color{#c92786}{9p-90}}3=9p−90

2

Add 

90

9090

 to both sides of the equation

3=9−90

3=9p-903=9p−90

3+90=9−90+90

3+{\color{#c92786}{90}}=9p-90+{\color{#c92786}{90}}3+90=9p−90+90

3

Simplify

Add the numbers

Add the numbers

93=9

93=9p93=9p

4

Divide both sides of the equation by the same term

93=9

93=9p93=9p

939=99

\frac{93}{{\color{#c92786}{9}}}=\frac{9p}{{\color{#c92786}{9}}}993=99p

5

Simplify

Divide the numbers

Cancel terms that are in both the numerator and denominator

Move the variable to the left

=313

p=\frac{31}{3}p=331

Answered by maheshchaudhari1305
0

3=9(-10)

3=9p-90

p =  \frac{31}{9}

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