Math, asked by indsmiley, 7 months ago

Solve the following equation: 3(y – 2) = 2(y – 1) – 3.

Answers

Answered by Anonymous
42

Answer:

3(y - 2) = 2(y - 1) - 3 \\  \\  =  > 3y - 6 = 2y - 2 - 3 \\  \\  \\  =  > 3y - 2y  =  - 5 + 6 \\  \\  \\  =  > y = 1

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Answered by qwwestham
6

The solution of the given equation is y = 1.

Given,

Equation:

3(y-2)=2(y-1)-3.

To find,

Solution of the given equation.

Solution,

It can be seen that the given equation here, is

3(y-2)=2(y-1)-3 \hfill ...(1)

Now, the above equation can be solved by simply expanding the brackets and simplifying the obtained equation.

So from (1), on expanding, we have,

3y-(3 \times 2)=2y - (2 \times 1) - 3

Simplifying,

3y-6=2y-2-3

Rearranging, by taking the terms with variables on the same side, we get,

\implies 3y-2y=6-2-3

\implies y=6-5=1

y = 1.

Solution of the equation: y = 1.

Therefore, the solution of the given equation is y = 1.

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