Question

solve the following equation 3(y-2) = 2(y-1) -3​

Answer 1

Answer:

3(y-2) = 2(y-1) -3,

=> 3y -6 = 2y-2-3,

=> y = 1.

Answer 2

Solution:

3(y – 2) = 2(y – 1) – 3

⇒ 3y – 6 = 2y – 2 – 3 (Removing the brackets)

⇒ 3y – 6 = 2y – 5

⇒ 3y – 2y = 6 – 5 (Transposing 6 to RHS and 2y to LHS)

⇒ y = 1

Thus y = 1