Math, asked by manjeetsingh43p66kko, 1 year ago

solve the following equation

Attachments:

Answers

Answered by siddhartharao77
1
 \frac{x^2 - (x+2)(x+3)}{6x+1} =  \frac{2}{3}

x^2 - (x + 2)(x + 3) * 3 = 2(6x + 1)

x^2 - (x^2 + 3x + 2x + 6) * 3 = 12x + 2

x^2 - x^2 - 5x - 6 * 3 = 12x + 2

(-5x - 6) * 3 = 12x + 2

-15x - 18 = 12x + 2

-27x = 20

x = -20/27.



Hope this helps!

siddhartharao77: :-)
GeniusYH: Please see inbox
siddhartharao77: ok
GeniusYH: And approve answers
GeniusYH: Please sir
siddhartharao77: Already approved that answer. Do check it.
GeniusYH: Thanks sir and again. Check inbox SIr pleas
GeniusYH: Below answer approve please correct
GeniusYH: It is*
Answered by GeniusYH
1
 Hello friend, 
The answer to your question is in the pic. 

Answer: x = (-20/27)
Explanation: Pic

Hope my answer helps you. 
Attachments:
Similar questions
Math, 7 months ago