Question

Solve the following equation;
3x+2y-26=0; 6x+y=31​

Answer 1

Answer:

3x+2Y-26=0

x=(26-2y)1/3

putting value of x in other equation

6(26-2y)1/3+y=31

52-4y+y=31

3y=52-31

3y=21

y=7

now putting y=7 in x=(26-2y)1/3

x=(26-2×7)1/3

x=12/3

×=4

Answer 2

$\Rightarrow\Huge\boxed{ x = 4 \:and \:y = 7}$

$\huge\underline\mathfrak\purple{Answer}$

$9x = 36. \\ \\ x = \cancel \frac{36}{9} . \\ \\ x = 4. \\ \\ \\ \\ 2y = 14. \\ \\ y = \cancel \frac{14}{2} . \\ \\ y = 7.$

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