Solve the following equation:
3x - y = 7; x + 4y = 11
(With step by step explanation)
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assume 3x-y=7 as eqn 1 and x+4y=11 as eqn 2
multiplying eqn 1 by 4
we get
12x-4y=28 eqn 3
adding eqn 2 and 3
we get
x+4y=11
+12x-4y=28
we get
13x=39
x=3
substitute x=3 in eqn 1
we get
y=2
therefore we get x=3 & y=2
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