Question

Solve the following equation: 4 6(n1) 34.

Answer 1

Step-by-step explanation:

3 ab (a + b) + 3 bc (b + c) + 3 ac (a + c) +6 abc = 3 [ ab ... which is equal to R.H.S of equation (1). ... =a² +b² + c²+2(ab+bc+ ca) now: (a+b+c)² (a+b+c)=(a + b + c)³=[a² +b² + ...

Answer 2

$\bigstar\quad\textrm{The Correct Question is to Solve for 'n' in : 4 + 6(n - 1) = 34}$

Subtracting 4 from Both Sides of the Given Equation

$\longrightarrow\rm{4+6\left(n-1\right)-4=34-4}\longrightarrow\rm{6\left(n-1\right)=30}$

Dividing Both Sides of the Given Equation by 6

$\longrightarrow\rm{\left(n-1\right)=30/6}\longrightarrow\rm{n-1=5}$

Adding 1 to Both Sides of the Given Equation

$\longrightarrow\rm{n-1=5}\longrightarrow\rm{n-1+1=5+1}\longrightarrow\rm{n=6}$