Question

Solve the following equation
√(4-x)+√(x+9)=5

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\red{ \sqrt{4 - x} + \sqrt{x + 9} = 5} \\ \sf\red{ = > {( \sqrt{4 - x} + \sqrt{x + 9} )}^{2} = {5}^{2} } \\ we \: know \: ({x + y})^{2} \sf\red{ = {x}^{2} + {y}^{2} + 2xy } \\ \sf\red{ = > 4 - x + x + 9 + 2 \times \sqrt{4 - x } \: \times \sqrt{x + 9} = 25 } \\ \sf\red{ = >13 + 2 \sqrt{4x + 36 - {x}^{2} - 9x} = 25 } \\ \sf\red{ = >2 \sqrt{4x + 3 - {x}^{2} - 9x} = 12 } \\ \sf\red{ = > \sqrt{ { - x}^{2} - 5x + 36} = 6 } \\ \sf\red{ = > { - x}^{2} - 5x + 36 = 36} \\ \sf\red{ = > {x}^{2} - 5x = 0} \\ \sf\red{ = >x(x - 5) = 0 } \\ \sf\red{x = 0 \: and \: x = 5}$